Answer:
x = [tex]\sqrt{26}[/tex]
Step-by-step explanation:
using pythagoras theorem
here [tex]\sqrt{13}[/tex] and [tex]\sqrt{13}[/tex] are the legs of the right angled triangle and x is hypotenuse.
a^2 + b^2 = c^2
[tex](\sqrt{ 13 })^2 + (\sqrt{13})^2 = x^2[/tex]
13 + 13 = x^2
26 = x^2
[tex]\sqrt{26}[/tex] = x
