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Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Limit Property [Multiplied Constant]: [tex]\displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)[/tex]
Derivatives
Definition of a Derivative: [tex]\displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle g(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}[/tex]

[tex]\displaystyle f(x) = \frac{3}{\sqrt{x - 4}}[/tex]

[tex]\displaystyle g(29)[/tex]

Step 2: Differentiate

Substitute in function [Function g(x)]: [tex]\displaystyle g(x) = \lim_{h \to 0} \frac{\frac{3}{\sqrt{x + h - 4}} - \frac{3}{\sqrt{x - 4}}}{h}[/tex]
Substitute in x [Function g(x)]: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{\frac{3}{\sqrt{29 + h - 4}} - \frac{3}{\sqrt{29 - 4}}}{h}[/tex]
Simplify: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{\frac{3}{\sqrt{25 + h}} - \frac{3}{5}}{h}[/tex]
Rewrite: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{\frac{15}{5\sqrt{25 + h}} - \frac{3\sqrt{25 + h}}{5\sqrt{25 + h}}}{h}[/tex]
[Subtraction] Combine like terms: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{\frac{15 - 3\sqrt{25 + h}}{5\sqrt{25 + h}}}{h}[/tex]
Factor: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{\frac{3(5 - \sqrt{25 + h})}{5\sqrt{25 + h}}}{h}[/tex]
Rewrite: [tex]\displaystyle g(29) = \lim_{h \to 0} \frac{3(5 - \sqrt{25 + h})}{5h\sqrt{25 + h}}[/tex]
Rewrite [Limit Property - Multiplied Constant]: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{5 - \sqrt{25 + h}}{h\sqrt{25 + h}}[/tex]
Root Conjugation: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{5 - \sqrt{25 + h}}{h\sqrt{25 + h}} \cdot \frac{5 + \sqrt{25 + h}}{5 + \sqrt{25 + h}}[/tex]
Multiply: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{-h}{5h\sqrt{25 + h} + h^2 + 25h}[/tex]
Factor: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{-h}{h(5\sqrt{25 + h} + h + 25)}[/tex]
Simplify: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{-1}{5\sqrt{25 + h} + h + 25}[/tex]
Evaluate limit [Limit Rule - Variable Direct Substitution]: [tex]\displaystyle g(29) = \frac{3}{5} \lim_{h \to 0} \frac{-1}{5\sqrt{25 + 0} + 0 + 25}[/tex]
Simplify: [tex]\displaystyle g(29) = \frac{3}{5} \cdot \frac{-1}{50}[/tex]
Multiply: [tex]\displaystyle g(29) = \frac{-3}{250}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e