Answer:
-63
Step-by-step explanation:
Given the expression:
[tex](1/8)^x + (1/8)^{x-2}[/tex]
Using the law of indices, this can be written as:
[tex](\frac{1}{8})^x-(\frac{1}{8} )^x * (\frac{1}{8})^{-2}\\(\frac{1}{8})^x (1-(\frac{1}{8})^{-2})\\(\frac{1}{8})^x(1-8^2)\\(\frac{1}{8})^x(-63)\\-63(\frac{1}{8})^x\\[/tex]
This shows that the value of A is -63
