Answer:
[tex]\huge\boxed{s=17}[/tex]
Step-by-step explanation:
ΔADB is the right triangle with a right angle in vertex B. We can use the Pythagorean theorem.
[tex]leg^2+leg^2=hypotenuse^2[/tex]
We have:
[tex]leg=15\\leg=8\\hypotenuse=s[/tex]
Substitute:
[tex]s^2=15^2+8^2\\\\s^2=225+64\\\\s^2=289\Rightarrow s=\sqrt{289}\\\\s=17[/tex]
