1davey29
1davey29 1davey29
  • 13-12-2016
  • Mathematics
contestada

Let f(x)=cos(arctanx). What is the range of f?
(a) {x|-(pi/2) (a) {x|0 (a) {x|0= (a) {x|-1 (a) {x|-1=

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Brenan
Brenan Brenan
  • 13-12-2016
-π/2 < arctan(x) < π/2

So cos(π/2) < cos(arctan(x)) < cos(0)

0 < cos(arctan(x)) < 1
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