The first thing you want to do is move that 48 to the other side. To do that, add 48 to both sides:
7x-5x/3(20x-8)=48
Now, the equation isn’t equal to zero… so it is solvable! Remember in order of operations: PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction. So, let’s start by multiplying the (-5x/3) by the components inside the parentheses to get rid of the parentheses altogether!
7x-100x/3x+40x/3=48
Since both the numerator and denominator have an “x” in them in “100x/3x”, you can cancel out the “x”s to just get 100/3, which is 33.333333
7x-100/3+40x/3=48
Let’s get rid of that 100/3 by adding it to both sides.
7x+40x/3=81.33333333333
Transform 7x to a fraction that can be added to 40x/3 (common denominators)
7x=7x/1
7x/1* (3/3)= 21x/3
Now, add the two fractions together
21x/3+40x/3= 61x/3
61x/3=81.333333333
Get rid of the 3 by multiplying on both sides:
61x= 244
Divide by 61 to get x
X=4
Hope this helped! Comment if you have any questions!
