I'm not sure what you're asking here
Step-by-step explanation:
[tex] \frac{9}{5c} + 32 = f[/tex]
[tex] \frac{9}{5c + 32} = f[/tex]
Assuming the former
[tex] \frac{9}{5c} + 32 = f \\ \frac{9}{5c} = f - 32 \\ \frac{9}{5} = c(f - 32) \\ c = \frac{9}{5(f - 32)} [/tex]
Assuming the latter
[tex] \frac{9}{5c + 32} = f \\ 9 = f(5c + 32) \\ 9 = 5cf + 32f \\ 9 - 32f = 5cf \\ \frac{9 - 32f}{5f} = c[/tex]
