ashajohns315 ashajohns315
  • 14-10-2021
  • Mathematics
contestada

Solve for x
5x + 6 < 3x + 7

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discipulus
discipulus discipulus
  • 14-10-2021

Answer:

[tex]5x + 6 < 3x + 7 \\ 5x - 3x < 7 - 6 \\ 2x < 1 \\ x < \frac{1}{2} [/tex]

Answer Link
2991ys
2991ys 2991ys
  • 14-10-2021

Answer:

x < 1/2

Step-by-step explanation:

5x + 6 < 3x + 7

2x + 6 < + 7

2x < 1

x < 1/2

Answer Link

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