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adioabiola

The value of Δy using the function y= 5x^3 as x goes from -2 to 1 is; Δy = 45

The question requests that Δy be computed according to the function, y = 5x³ as x goes -2 to 1.

  • Δy = y2 - y1

where:

  • y1 = 5(-2)³

  • y1 = -40

and

  • y2 = 5(1)³

  • y2 = 5

Therefore,

  • Δy = y2 - y1

  • Δy = 5 - (-40)

Δy = 45.

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