[tex]\text{Given that ,}\\\\\text{Length,}~ l = (2y+5)~\text{units.}\\\\\text{Width, } w= 3~\text{units.}\\\\\\\text{Area} = lw = (2y+5)(3) = (6y+15) ~~ \text{units}^2.\\\\\\\text{Perimeter} =2(l+w) = 2(2y+5 +3) = 2(2y+8) = (4y+16)~~ \text{units}.[/tex]
