Answer:
[tex]y_1=0,y_2=\frac{3}{2},y_3=\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]4y^3-9y=0[/tex]
[tex]y(4y^2-9)=0[/tex]
[tex]y(2y-3)(2y+3)=0[/tex] <-- Difference of squares
