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  • 12-01-2017
  • Mathematics
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can you please help with all (answers) I have a lot

can you please help with all answers I have a lot class=

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Аноним Аноним
  • 13-01-2017
4+15/3*4-2
4+5*4-2
4+20-2
24-2
22
1st 15/3=5
2nd 5*4=20
3rd 4+20=24
4th 24-2=22 
so your answer is 22 

3+9^2/9*4-5
3+18/9*4-5    
3+2*4-5
3+8-5
11-5
6
1st 9 to the second power will be 9*2 so that is 18
2nd 18/2=9
3rd 2*4=8
4th 3+8=11
5th 11-5=6
so your answer is 6 

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