Answer: g(x) = 5x+1
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Work Shown:
[tex]h(x) = (f \circ g)(x)\\\\h(x) = f(g(x))\\\\f(x) = x^2 - x\\\\f(g(x)) = (g(x))^2 - (g(x))\\\\f(g(x)) = (5x+1)^2 - (5x+1)\\\\h(x) = (5x+1)^2 - (5x+1)\\\\[/tex]
Therefore, g(x) = 5x+1
