Answer:
[tex]x=\frac{7}{2}[/tex] and [tex]x=-2[/tex]
Step-by-step explanation:
[tex]\frac{x^2}{3x+14}=\frac{1}{2}[/tex]
[tex]2x^2=3x+14[/tex]
[tex]2x^2-3x-14=0[/tex]
[tex]x^2-3x-28=0[/tex] <-- Slide-and-divide method
[tex](x-7)(x+4)=0[/tex]
[tex](2x-7)(x+2)=0[/tex]
[tex]x=\frac{7}{2}[/tex] and [tex]x=-2[/tex]
