Respuesta :

xenia168

Answer:

y ≥ - 0.8

Step-by-step explanation:

[tex]\sqrt{25y^2 +40y+16}[/tex] = 5y + 4

[tex]\sqrt{(5y+4)^2}[/tex] = 5y + 4

5y + 4 = 5y + 4 and 5y + 4 ≥ 0 ⇒ y ≥ - 0.8

y ∈ [ - 0.8 , ∞ )

- ( 5y + 4 ) = 5y + 4

10y = - 8

y = - 0.8

The answer is y ≥ - 0.8

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