Answer:
the integers are either -3 , -2. or
2,3
Step-by-step explanation:
[tex]x \times x + 1 = {x}^{2} + 1 \\ x + x + 1 = (2x + 1)3 = 6x + 3 \\ 6x + 3 - 3 = {x}^{2} + 1 \\ 6x = {x}^{2} + 1 \\ {x}^{2} - 6x + 1 = 0 \\ (x + 3)( x - 2) \\ x = - 3 \: x = 2 \\ [/tex]
