Answer:
[tex]f(g(x))=(2x^2+4)-\frac{2}{4}\\g(f(x))=2(x-\frac{2}{4})^2+4[/tex]
Step-by-step explanation:
Given:
[tex]f(x)=x-\frac{2}{4}\\g(x)=(2x^2+4)[/tex]
F of G:
[tex]f(g(x)=(g(x))-\frac{2}{4}\\f(g(x))=(2x^2+4)-\frac{2}{4}[/tex]
G of F:
[tex]g(f(x))=2(f(x))^2+4\\g(f(x))=2(x-\frac{2}{4})^2+4[/tex]
