Answer:
Step-by-step explanation:
y=∫ln(x^2) (2x) dx
=ln (x^2) (x^2)-∫(2x/x^2) (x^2) dx+c
=x² ln (x²)-∫2x dx+c
=x²ln(x²)-x²+c
=x²[ln(x²)-1]+c
integration is between an interval so don't understand at x=3
