kemyiakelleyparrish0 kemyiakelleyparrish0
  • 15-06-2022
  • Mathematics
contestada

what are the solution of the quadratic equation (x-8)3-13x(x-8)+3=0? use u substitution to solve.

Respuesta :

199932
199932 199932
  • 15-06-2022

[tex]3(x - 8) - 13x(x - 8) + 3 = 0 \\ 3x - 24 - 13 {x}^{2} + 104x + 3 = 0 \\ - 13 {x}^{2} + 107x - 21 = 0 \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a } \\ a = - 13 \\ b = 107 \\ c = - 21 \\ x = \frac{ - 107 + - \sqrt{ {107}^{2} - 4(13)( - 21)} }{2( - 13)} \\ x1 = \frac{107 - \sqrt{10357} }{26} \\ x2 = \frac{107 + \sqrt{10357} }{26} [/tex]

Hope it helps

Please give brainliest

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