Answer + Step-by-step explanation:
an= 4(2)ⁿ⁻¹
First term (n = 1) :
a1= 4(2)¹⁻¹ = 4(2)⁰ = 4×(1) = 4
Second term (n = 2) :
a2= 4(2)²⁻¹ = 4(2)¹ = 4×(2) = 8
Third term (n = 3) :
a3= 4(2)³⁻¹ = 4(2)² = 4×(4) = 16
Fourth term (n = 4) :
a4= 4(2)⁴⁻¹ = 4(2)³ = 4×(8) = 32
