jackrch
jackrch
13-03-2017
Mathematics
contestada
sinΘ = 15/17 and Θ lies in Q1, find cos 2Θ
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LammettHash
LammettHash
13-03-2017
[tex]\cos^2\theta=1-\sin^2\theta[/tex]
[tex]\cos^2\theta=1-\dfrac{225}{289}=\dfrac{64}{289}[/tex]
[tex]\cos2\theta=\cos^2\theta-\sin^2\theta[/tex]
[tex]\cos2\theta=\dfrac{64}{289}-\dfrac{225}{289}=-\dfrac{161}{289}[/tex]
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