heplmeplz
heplmeplz
14-03-2017
Mathematics
contestada
cos(3x) = cos^2x - 3sin^2x cosx
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LammettHash
LammettHash
14-03-2017
[tex]\cos3x=\cos(2x+x)=\cos2x\cos x-\sin2x\sin x[/tex]
[tex]=(\cos^2x-\sin^2x)\cos x-2\sin^2x\cos x[/tex]
[tex]=\cos^3x-3\sin^2x\cos x[/tex]
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