Respuesta :

smpurvis
A+b+c=130 a,b,c  ip  cu 2,3,4 2a=3b=4c=k a=k/2 b=k/3 c=k/4 k/2 + k/3+ k/4= 130  aducem la acelasi numitor (12) 6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30
6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30, hope that helps!!

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