Seudónimo Seudónimo
  • 11-04-2017
  • Mathematics
contestada

help with math question please
thanks so much

help with math question please thanks so much class=

Respuesta :

Аноним Аноним
  • 11-04-2017
[tex] \frac{-b(+/-) \sqrt{b^{2} + 4ac}}{2a} [/tex]

where ax^2+bx+c=0

a=1
b=-2
c=-4

Just plug in.

x=1+√5
x=1-√
Answer Link
Аноним Аноним
  • 11-04-2017
[tex]x=1 \sqrt{5} [/tex]
[tex]x=3.23606797,-1.23606797[/tex]
Hope my answer helped!
Answer Link

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