dchagoya
dchagoya
15-05-2014
Mathematics
contestada
Use long division.
(30x³+4x²-150)÷(3x-5)
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kate200468
kate200468
15-05-2014
[tex]30x^3+4x^2-150=10x^2(3x-5)+18x(3x-5)+30(3x-5)=\\ \\=(3x-5)(10x^2+18x+30)\\\\ \\ (30x^3+4x^2-150):(3x-5)= \frac{(3x-5)(10x^2+18x+30)}{3x-5} =10x^2+18x+30[/tex]
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