Respuesta :

mreijepatmat
If so:

f(n) = 2n² + 4

for n= 0 → f(0) = 2(0) + 4 → f(0) = 4
for n= 1 → f(1) = 2(1²)+ 4 → f(1) = 6
for n= 2 → f(2) = 2(2²)+ 4 → f(2) = 12
for n= 3 → f(3) = 2(3²)+ 4 → f(3) = 22   and so on and so forth

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