Respuesta :


[tex] {x}^{2} - 4x - 9 = 29 \\ {x}^{2} - 4x - 38 = 0 \\ \\ x12 = \frac{ - b \frac{ + }{ - } \sqrt{d} }{2} \\ d = {b}^{2} - 4ac \\ d = 16 + 152 = 168 \\ \\ x1 = \frac{4 - \sqrt{168} }{2} \\ x2 = \frac{4 + \sqrt{168} }{2} [/tex]
nullgaming650
Solve for x in the equation x^2-4x-9=29

The Answer Is

X=168

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