Answer is: volume of the sample is 36,2 mL.
V₁(sample) = 17 mL.
T₁(sample) = −112°C = -112 + 273,15 = 161,15 K.
T₂(sample) = 70°C = 70 + 273,15 = 343,15 K.
V₂(sample) = ?
Charles' Law: V₁/T₁ = V₂/T₂.
17 mL/161,15 K = V₂/343,15 K.
161,15 K · V₂ = 17 mL · 343,15 K
V₂ = 5833,55 K·mL ÷ 161,15 K
V₂ = 36,2 mL.
