Respuesta :

"scalar" multiplication is very straightforward,

[tex]\bf A= \begin{bmatrix} 1&4\\ 5&2 \end{bmatrix}\qquad -2A=\begin{bmatrix} -2\cdot 1&-2\cdot 4\\ -2\cdot 5&-2\cdot 2 \end{bmatrix}\implies \begin{bmatrix} -2&-8\\ -10&-4 \end{bmatrix}[/tex]

Otras preguntas