nicholas33 nicholas33

15-02-2018
Physics

contestada

Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is the vacuum cleaner?

Respuesta :

SatansGF SatansGF

16-02-2018

Efficiency = 45J/120J = 0.375

Or

0.375 * 100% = 37.5 %

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