Respuesta :

dy/dx = 1/(6x + 5)^3

dy/dx = (6x + 5)^-3

Using the linear extension of the algebraic integral we have

y =  1/6 * (6x + 5)^(-3+1)  / (-3+1)

   =  1/6 * 1 / (6x + 5)^2 / -2

   =   - 1 / [12(6x + 5)^2 ]  +  C  ( where C is constant of integration)


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