joseg8500p5hkpx
joseg8500p5hkpx
12-03-2018
Mathematics
contestada
y= (x^3 +1)^2, then dy/dx=
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annacduffy
annacduffy
12-03-2018
dy/dx = (x^3+1)/y
ydy = (x^3+1)dx
integrating both side gives you 1/2*y^2= 1/4*x^4+x +C
since x=1,y=2 ---> 1/2*2^2=1/4*1^4+1+C ----> C=3/4
---> 1/2*y^2=1/4*x^4+x + 3/4
x=2 ----> y^2= [1/4*2^4 + 2 +3/4]*2 = 27/2
y= +/- sqrt(27/2)
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