sbrackett727p6s7p5
sbrackett727p6s7p5
16-04-2018
Physics
contestada
help with 26 please:):)
Respuesta :
AL2006
AL2006
16-04-2018
(25 watts)·(1 kw/1000 watts)·(1 year)·(365 day/year)·(24 hr/day)·(8¢ / kw-hr)
= (25·1·1·365·24·8) / (1000) (watts-kw-year-day-hour-¢ / watts-year-day-kWh)
= (1,752,000) / (1000) ¢
=
$ 17.52
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