[tex] {x}^{2} - 4x + 5 = 0 \\ {x}^{2} - 4x = - 5 \\ \\ { (\frac{b}{2} )}^{2} = ( \frac{ - 4}{2} ) = ( { - 2})^{2} = 4 \\ {x}^{2} - 4x + 4 = - 5 + 4 \\ {(x - 2)}^{2} = - 1 \\ {(x - 2)}^{2} + 1[/tex]
The last line is in vertex form, and can see the vertex is located at (2,1).
